diff --git a/td2.md b/td2.md
index 747a7c1..e48e764 100644
--- a/td2.md
+++ b/td2.md
@@ -3,24 +3,20 @@
 ## 1. Nombre de clients
 
 ```sql
-select count(*) from customers;
 ```
 
 ### 2. Nombre d'albums
 
 ```sql
-select count(*) from albums;
 ```
 ### 3. Nombre d'artistes
 
 ```sql
-select count(*) from artists;
 ```
 
 ### 4. Liste des pays
 
 ```sql
-select distinct country from customers;
 ```
 
 Utilisation de `distinct` pour supprimer les doublons.
@@ -28,85 +24,55 @@ Utilisation de `distinct` pour supprimer les doublons.
 ### 5. Nombre de clients par pays
 
 ```sql
-select country, count(*) from customers group by Country order by count(*) desc;
+
 ```
 
 ### 6. Nombre de pistes par genre
 
 ```sql
-select g.Name, count(*) as nb from tracks t
-inner join genres g on g.GenreId = t.GenreId
-group by g.GenreId order by nb desc;
+
 ```
 
 ### 7. Nombre d'albums par artiste
 
 ```sql
-select a.Name, count(*) as nb from artists a
-inner join albums b on b.ArtistId = a.ArtistId
-group by a.Name order by nb desc;
+
 ```
 
 ### 8. Nombre de piste par artiste
 
 ```sql
-select a.Name, count(*) as nb from artists a
-inner join albums b on a2.ArtistId = a.ArtistId
-inner join tracks t on t.AlbumId = b.AlbumId
-group by a.Name
-order by nb desc;
+
 ```
 
 ### 9. Nombre de minute de musique par album
 
 ```sql
-select a.Title , sum(t.Milliseconds/60000) as duree
-from tracks t
-inner join albums a on a.AlbumId = t.AlbumId
-group by a.Title
-order by duree desc;
+
 ```
 
 ### 10. Recette par piste
 
 ```sql
-select t.Name, sum(ii.UnitPrice*ii.Quantity) as recette
-from tracks t
-inner join invoice_items ii on ii.TrackId = t.TrackId
-group by t.Name order by recette desc;
+
 ```
 
 ### 9. Recette par album
 
 ```sql
-select a.Title, sum(ii.UnitPrice*ii.Quantity) as recette
-from tracks t
-inner join invoice_items ii on (ii.TrackId = t.TrackId)
-inner join albums a on a.AlbumId = t.AlbumId
-group by a.Title
-order by recette desc;
+
 ```
 
 ### 10. Les 3 meilleurs clients
 
 ```sql
-select c.FirstName, c.LastName, sum(i.Total) as total
-from customers c
-inner join invoices i on i.CustomerId = c.CustomerId
-GROUP by c.CustomerId
-order by total DESC
-limit 3;
+
 ```
 
 ### 11. Les genres écoutés par Isabelle Mercier
 
 ```sql
-select distinct g.Name from genres g
-inner join tracks t  on t.GenreId  = g.GenreId
-inner join invoice_items ii on ii.TrackId = t.TrackId
-inner join invoices i on ii.InvoiceId = i.InvoiceId
-inner join customers c  on c.CustomerId = i.CustomerId
-where c.FirstName = 'Isabelle' and c.LastName ='Mercier';
+
 ```
 Attention l'égalité est stricte sur FirstName et LastName (respect des majuscules / minuscules)
 
@@ -115,23 +81,19 @@ Attention l'égalité est stricte sur FirstName et LastName (respect des majuscu
 ### 12. Recette après le 01/05/2013
 
 ```sql
-select sum(i.Total) from invoices i where i.InvoiceDate > DATETIME('2013-05-01');
+
 ```
 
 ### 13. Recette entre le 15/04/2012 et le 20/06/2012
 
 ```sql
-select sum(i.Total)
-from invoices i
-where i.InvoiceDate between DATETIME('2012-04-15') and DATETIME('2012-06-20');
+
 ```
 
 ### 14. Recette du mois de février 2012
 
 ```sql
-select sum(i.Total)
-from invoices i
-where STRFTIME('%m/%Y', i.InvoiceDate) = '02/2012'
+
 ```
 
 STRFTIME (string from datetime) permet de formater au format de texte un date. Le format est complètement libre et personnalisable.
@@ -139,44 +101,33 @@ STRFTIME (string from datetime) permet de formater au format de texte un date. L
 ### 15. Recettes par mois
 
 ```sql
-select STRFTIME('%Y-%m', i.InvoiceDate) as mois,
-  sum(i.Total)
-from invoices i
-group by mois
-order by mois
+
 ```
 
 ### 16. Recette de l'année 2013
 
 ```sql
-select sum(i.Total)
-from invoices i
-where STRFTIME('%Y', i.InvoiceDate) = '2013'
+
 ```
 ## Recherche sur le texte
 
 ### 17. Liste des pistes qui contiennent le mot Love
 
 ```sql
-select t.Name from tracks t
-where t.NAME LIKE '%love%';
+
 ```
 L'opérateur LIKE ne tient pas compte de la différence minuscule/majuscule
 
 ### 18. Liste des pistes qui contiennent les lettres Sun
 
 ```sql
-select t.Name from tracks t
-where t.NAME LIKE '%SUN%';
+
 ```
 
 ### 19. Liste des pistes qui contiennent le mot Sun
 
 ```sql
-select t.Name from tracks t
-where t.NAME LIKE 'SUN %' OR
-      t.NAME LIKE '% SUN' OR
-      t.NAME LIKE '% SUN %';
+
 ```
 
 ## Cohérence
@@ -184,12 +135,7 @@ where t.NAME LIKE 'SUN %' OR
 ### 20. Le total de chaque facture est il juste ?
 
 ```sql
-select i.Total, sum(ii.UnitPrice*ii.Quantity) as somme,
-printf('%.20f', i.Total - sum(ii.UnitPrice*ii.Quantity))
-from invoices i
-inner join invoice_items ii on ii.InvoiceId = i.InvoiceId
-group by i.InvoiceId
-HAVING Abs(i.Total - somme) >= 0.01
+
 ```
 
 ou en utilisant ROUND : HAVING i.Total <> Round(somme,2)
@@ -197,7 +143,5 @@ ou en utilisant ROUND : HAVING i.Total <> Round(somme,2)
 ### 21. Existe t il des pistes dont le prix unitaire a évolué ?
 
 ```sql
-select t.Name from tracks t
-left join invoice_items ii on ii.TrackId = t.TrackId
-where t.UnitPrice <> ii.UnitPrice
+
 ```
diff --git a/td2.sql b/td2.sql
new file mode 100644
index 0000000..843eed2
--- /dev/null
+++ b/td2.sql
@@ -0,0 +1,105 @@
+select count(*) from customers;
+
+select count(*) from albums;
+
+select count(*) from artists;
+
+select distinct country from customers;
+
+select country, count(*) from customers group by Country order by count(*) desc;
+
+select g.Name, count(*) as nb from tracks t
+inner join genres g on g.GenreId = t.GenreId
+group by g.GenreId order by nb desc;
+
+select a.Name, count(*) as nb from artists a
+inner join albums b on b.ArtistId = a.ArtistId
+group by a.Name order by nb desc;
+
+select a.Name, count(*) as nb from artists a
+inner join albums b on a2.ArtistId = a.ArtistId
+inner join tracks t on t.AlbumId = b.AlbumId
+group by a.Name
+order by nb desc;
+
+select a.Title , sum(t.Milliseconds/60000) as duree
+from tracks t
+inner join albums a on a.AlbumId = t.AlbumId
+group by a.Title
+order by duree desc;
+
+
+select t.Name, sum(ii.UnitPrice*ii.Quantity) as recette
+from tracks t
+inner join invoice_items ii on ii.TrackId = t.TrackId
+group by t.Name order by recette desc;
+
+
+select a.Title, sum(ii.UnitPrice*ii.Quantity) as recette
+from tracks t
+inner join invoice_items ii on (ii.TrackId = t.TrackId)
+inner join albums a on a.AlbumId = t.AlbumId
+group by a.Title
+order by recette desc;
+
+select c.FirstName, c.LastName, sum(i.Total) as total
+from customers c
+inner join invoices i on i.CustomerId = c.CustomerId
+GROUP by c.CustomerId
+order by total DESC
+limit 3;
+
+
+select distinct g.Name from genres g
+inner join tracks t  on t.GenreId  = g.GenreId
+inner join invoice_items ii on ii.TrackId = t.TrackId
+inner join invoices i on ii.InvoiceId = i.InvoiceId
+inner join customers c  on c.CustomerId = i.CustomerId
+where c.FirstName = 'Isabelle' and c.LastName ='Mercier';
+
+
+select sum(i.Total) from invoices i where i.InvoiceDate > DATETIME('2013-05-01');
+
+
+select sum(i.Total)
+from invoices i
+where i.InvoiceDate between DATETIME('2012-04-15') and DATETIME('2012-06-20');
+
+
+select sum(i.Total)
+from invoices i
+where STRFTIME('%m/%Y', i.InvoiceDate) = '02/2012'
+
+
+select STRFTIME('%Y-%m', i.InvoiceDate) as mois,
+  sum(i.Total)
+from invoices i
+group by mois
+order by mois
+
+select sum(i.Total)
+from invoices i
+where STRFTIME('%Y', i.InvoiceDate) = '2013'
+
+select t.Name from tracks t
+where t.NAME LIKE '%love%';
+
+select t.Name from tracks t
+where t.NAME LIKE '%SUN%';
+
+select t.Name from tracks t
+where t.NAME LIKE 'SUN %' OR
+      t.NAME LIKE '% SUN' OR
+      t.NAME LIKE '% SUN %';
+
+select i.Total, sum(ii.UnitPrice*ii.Quantity) as somme,
+printf('%.20f', i.Total - sum(ii.UnitPrice*ii.Quantity))
+from invoices i
+inner join invoice_items ii on ii.InvoiceId = i.InvoiceId
+group by i.InvoiceId
+HAVING Abs(i.Total - somme) >= 0.01
+
+
+select t.Name from tracks t
+left join invoice_items ii on ii.TrackId = t.TrackId
+where t.UnitPrice <> ii.UnitPrice